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1.2x^2-4.5x=0
a = 1.2; b = -4.5; c = 0;
Δ = b2-4ac
Δ = -4.52-4·1.2·0
Δ = 20.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{20.25}}{2*1.2}=\frac{4.5-\sqrt{20.25}}{2.4} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{20.25}}{2*1.2}=\frac{4.5+\sqrt{20.25}}{2.4} $
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